Step I : Calculate Xu,lim
Step II : Based on Xu,lim with respect to depth of flange (Df), Compute MoR,lim.
Step III : If BMu>MoR,lim, Doubly Reinforced Section would be designed; If BMu < MoR,lim then Singly Reinforced Section is designed.
Step IV: Assume Xu = Df and Compute MoR.
Step V :If BMu<MoR1, The Neutral Axis is in flange and section behaves as rectangular section and Ast is given as,
Step VI: If MoR1 < BMu < MoR,lim; then Neutral axis is in web region.
Now,
Xu = 7/3 Df and Compute MoR2
Step VII : If MR2 < BMu <MoR,lim ; Xu > 7/3 Df
Df < 3/7 Xu
Calculate exact depth of Neutral axis,
BMu = MoR
Xu = ?
To Compute Ast, C=T
Ast = ?
Step VIII : If MoR1<BMu<MR2
Df < Xu < 7/3 Df
Df > 3/7 Xu
To compute exact depth of Neutral Axis,
BMu = MoR
For Ast,
Step 9 : Ast Computed above must be within Permissible Limit.
Ast/(bw d) > 0.87/fy
Ast should be less than equal to min of {Ast,lim and 0.045 bw d}
Design Example :
Que. Design a section shown below for Ultimate BM of 700 KN-m. This section is used in simply Supported beam of effective span of 7m.