Design Steps of Singly Reinforced Section

Case I : Section size is given, To find Ast = ?

  1. Calculate design/factored/Ultimate BM from Service/Working/Characteristics Moment.
  2. Calculate Limiting Moment of Resistance for given section. [ MoR,lim = Qbd2 ]
  3. If BMu > MoR,lim; Provide doubly Reinforced section. If BMu < MoR,lim; Provide Under reinforced Section.
  4. BMu = MoR (from Compression Side), BMu = 0.36 fck Xu b (d-0.42 Xu)
  5. Compute Ast from C=T, 0.36 fck Xu b = 0.87 fy Ast, or instead of step 4 and 5,

6. Area of steel is to be checked for its permissible limit


Case 2 : When Section size & area of steel are to be calculated

  1. Calculate factored/ Ultimate design BM
  2. Assume suitable of b/d ratio.

Lateral buckling : 0.3<b/d<0.7 (uneconomical)

In general, b/d = 0.5

3. The beam size may be considered as any of the following , 115mm, 250mm, 300mm, 350mm etc.

4. Provide d slightly greater than d calculated. generally, d = 1.05 * d,calculated (This is done to keep section under-reinforced)

5. To compute dreqrd for balanced section,

BMu = MoR, lim

BMu = Qlim bd2

6. For Ast,

BMu = C X LA = 0.36 fck Xu b (d-0.42 Xu)

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